How to calculate salt for a brine
For a recipe that calculates salt from water weight, multiply the water mass by the target percentage and divide by 100. For example, 1,000 g water at 3% needs 30 g salt. The finished mixture weighs 1,030 g.
Salt = water × percentage ÷ 100
1,000 g × 3 ÷ 100 = 30 g
When the recipe defines percentage as salt divided by the finished solution mass, salt belongs in the denominator too. Starting with 1,000 g water at a true 3% solution concentration requires about 30.93 g salt.
Salt = water × percentage ÷ (100 − percentage)
1,000 g × 3 ÷ 97 ≈ 30.93 g
For a recipe that specifies salt against food plus water weight, add those two masses before applying the percentage. This is an ingredient ratio. It is not a measurement of salt inside the food after brining.
Salt = (food + water) × percentage ÷ 100
(500 g + 1,000 g) × 3 ÷ 100 = 45 g
Salt per litre of water
Water-weight method: 1 litre water ≈ 1,000 g. These are arithmetic examples, not food-specific recommendations.
| Recipe percentage | Salt to weigh | Solution percentage |
|---|
| 1% | 10 g | 0.99% |
| 2% | 20 g | 1.96% |
| 3% | 30 g | 2.91% |
| 4% | 40 g | 3.85% |
| 5% | 50 g | 4.76% |
| 6% | 60 g | 5.66% |
| 8% | 80 g | 7.41% |
| 10% | 100 g | 9.09% |
A litre of water is not a litre of finished brine. Adding salt changes both mass and volume.